Question

The circle has center O, and its radius is 9 in. Given that m

Answer 1

For this case we can do the following:

`AB=2\pi r((x)/(360))=2\pi\cdot9in((40)/(360))=2\pi=6.283\text{ in}`

And then the lenght of the ARC ACB would be:

`\text{ACB}=2\pi(9)-2\pi=2\pi(9-1)=16\pi=50.265in`

Final answer 16 pi