Question

What is the equation of a line that passes through the points (3,6) and (8, 4)?

3
Oy= 22
o - -
o v x 27
0 - 22/x - 29
oy- - 2 x + 38

Answer 1

In the equation y=mx+b, 'm' is the slope of the line and 'b' is the y-intercept.

First, you should find the slope of the line. To do this, use the equation M=y2-y1/x2-x1. Using the two given points (3,6) and (8,4), you can solve for M.

M=4-6/8-3

M=-2/5 (-0.4 in decimal form)

Now, your equation is y=-0.4x+b

Next you must solve for b to find the y-intercept. You can do this by subbing one of the given points in for x and y.

Using the point (3,6):

y=-0.4x+b

6=-0.4(3)+b

6=-1.2+b

Isolate b:

6+1.2=b

b=7.2

And now you have the equation of the line!

y=-0.4x+7.2 (IN FRACTION FORM: y=-2/5x+36/5)

Explanation: