Question

A chemist used a solution of copper sulfate (CuSo4) with a concentration of 0.00095 mol l-1. If they were preparing one litre of this solution, what mass of copper sulfate should they weigh out?For your calculation use the following relative atomic mass (RAM) values:RAM (Cu) = 63RAM (S) = 32RAM (O) = 16

Answer 1

mass of copper sulfate = 0.151 g

Step-by-step explanation

Given:

number of moles of CuSo4 = 0.00095 mol.L^-1

Volume = 1 L

We know:

Molar mass of CuSO4 = 159,61 g/mol

Required: Mass of copper sulfate

Solution:

Step 1: Find the number of moles of CuSO4

C = n/V where C is the molarity or concentration, n is the moles and V is the volume

n = C x V

n = 0.00095 mol.L^-1 x 1 L

n = 0.00095 mol

Step 2: Find the mass of copper sulfate

n = m/M where n is the moles, m is the mass and M is the molar mass

m = n x M

m = 0.00095 mol x 159 g/mol

m = 0.151 g