(a) First, we need to write the combustion reaction for ethanol (CH3CH2OH)
CH3CH2OH + O2 → CO2 + H2O
Then, we need to balance this equation. To do that, remember to start with C, then move on to H and finally balanced the amount of O:
CH3CH2OH + 3 O2 → 2 CO2 + 3 H2O
(b) Since this is a reaction that realeases heat (726.7 kJ /mol of ethanol), we know that is an exothermic reaction and the general scope of an enthalpy diagram would be like this:
Where, for the combustion of ethanol, the reactants would be CH3CH2OH + O2, the products would be CO2 + H2O, and ΔH would be -726.7 kJ/mol