Question

If X and A are counting numbers is X over negative A (x^-a) less than or greater than 1 ?

Answer 1

X & A are counting numbers. This means that a is a number that comes after x just like 2 comes after 1: a > x

Let's assume that x = 1 & a = 2

`x^(-a)\Rightarrow1^(-2)=(1)/(1^2)=1`

If x = 2 & a = 3, we have:

`x^(-a)\Rightarrow2^(-3)=(1)/(2^3)=(1)/(8)`

If x = 3 & a = 4, we have:

`x^(-a)\Rightarrow3^(-4)=(1)/(3^4)=(1)/(81)`

Except for the first scenario where x = 1 & a = 2 where we got x ^(-a) equal to 1, for every other subsequent value, we will obtain values less than 1