36.9k views
3 votes
Select the correct answer from each drop-down menu.In the first box it’s either (equal to) or (not equal to)In the Second box it’s either (are) or (are not)

Select the correct answer from each drop-down menu.In the first box it’s either (equal-example-1
User Elkvis
by
8.3k points

1 Answer

5 votes

To find h(k(x)), we have to replace the x-variable of h(x) with the function k(x).


\begin{gathered} h(k(x))=5(\sqrt[]{5x+1})^2-1=5(5x+1)-1=25x+5-1 \\ h(k(x))=25x+4 \end{gathered}

Then, find k(h(x)) using the same process.


\begin{gathered} k(h(x))=\sqrt[]{5(5x^2-1)+1}=\sqrt[]{25x^2-5+1} \\ k(h(x))=\sqrt[]{25x^2-4} \end{gathered}

As you can observe, the functions obtained are not equal.

Therefore, h(k(x)) is not equal to k(h(x)).

Also, the functions h and k are not inverse functions because the coefficient 5 would be as a denominator.

User Genericrich
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories