Question

How many atoms are contained in (6.73x10^2) grams of neon?

Answer 1

`atom\text{ of Neon}=2.01*10^(25)atoms`

Explanations:

According to the Avogadro's constant

`1mole\text{ of substance}=6.02*10^(23)atoms`

Given the following parameter

Mass of Neon = 6.73 * 10^2grams = 673grams

Determine the moles of Neon

`\begin{gathered} mole\text{ of Neon}=\frac{mass}{molar\text{ mass}} \\ mole\text{ of Neon}=(673)/(20.18) \\ mole\text{ of Neon}=33.35moles \end{gathered}`

Convert moles to atoms

`\begin{gathered} atom\text{ of Neon}=33.35*6.02*10^(23)atoms \\ atom\text{ of Neon}=200.77*10^(23)atoms \\ atom\text{ of Neon}=2.01*10^(25)atoms \end{gathered}`