Question

I need help with exercise 8-3 I already did 15. So I need the rest

Answer 1

STEP 1: we create a table of values for y and x as shown below;

For each value of x, we get a corresponding value for y;

`\begin{gathered} y=x^{2^{}}-2x-15 \\ \text{When x=-4} \\ y=(-4)^2-2(-4)-15=9 \end{gathered}`

We continue with this process till when x = 6

`\begin{gathered} \text{When x=-3} \\ y=(-3)^2-2(-3)-15=0 \\ \text{When x=-2} \\ y=(-2)^2-2(-2)-15=-7 \\ \text{When x=-1} \\ y=(-1)^2-2(-1)-15=-12 \\ \text{When x=0} \\ y=(0)^2-2(0)-15=-15 \\ \text{When x=1} \\ y=(1)^2-2(1)-15=-16 \\ \text{When x=2} \\ y=(2)^2-2(2)-15=-15 \\ \text{When x=3} \\ y=(3)^2-2(3)-15=-12 \\ \text{When x=4} \\ y=(4)^2-2(4)-15=-7 \\ \text{When x=5} \\ y=(5)^2-2(5)-15=0 \\ \text{When x=6} \\ y=(6)^2-2(6)-15=9 \\ \end{gathered}`