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Find the equation of the line that passes through (-1,5) and (0,1)

User Sergnsk
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We have to find the equation of the line that passes through the points (-1,5) and (0,1). We will write the equation in the slope-intercept form, which is given by:


y=mx+b

Where m represents the slope of the function, and b the y-intercept. We will find the slope, and then the y-intercept.

1. Finding the slope

For finding the slope we will use the formula:


m=\frac{y_2-y_1_{}}{x_2-x_1}

where (x₁,y₁) and (x₂,y₂) are two points that passes through the line. In this case, the points (-1,5) and (0,1).

Replacing, we obtain:


m=(1-5)/(0-(-1))=(-4)/(1)=-4

Thus, the slope is -4.

2. Finding the y-intercept

For doing this step, we want to know the value of the function when x equals zero. But, as we have that the line passes through (0,1), this means that this value will be 1. This is, the y-intercept is 1.

3. Putting all together

Now, we just have to put the values obtained in the slope-intercept form:


\begin{gathered} y=mx+b \\ y=-4x+1 \end{gathered}

And this means that the equation of the line that passes through (-1,5) and (0,1) is y=-4x+1.

User Kenta Nomoto
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