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Triangle ABC has vertices A= (-1, 7), B = (1, 1) and C= (3, 8). Triangle A'B'C' is formed when Triangle ABC is translated right by 4 and up by 2. Which statement is true? Choose all that apply. O The angles of Triangle ABC and Triangle A'B'C' are the same. O Triangle A'B'C is located in Quadrant 1. The perimeter of Triangle ABC and Triangle A'B'C' are the same.

User ZenTheo
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1 Answer

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The coordinates of XYZ are given as follows;


\begin{gathered} X(-1,7),Y(1,1),Z(3,8) \\ \text{When the triangle is translated by 4 units to the right then we add 4 to the x coordinates} \\ \text{Also when its translated up by 2 units we add 2 to the y coordinates} \\ \text{Hence we now have;} \\ X\text{'(-1+4, 7+2)} \\ X^(\prime)(3,9) \\ Y^(\prime)(1+4,1+2) \\ Y^(\prime)(5,3) \\ Z^(\prime)(3+4,8+2) \\ Z^(\prime)(7,10) \end{gathered}

The correct answer therefore is option A

X' (3, 9)

Y' (5, 3)

Z' (7, 10)

User Mark Simon
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