Question

A car dealership decides to select a month at random for its annual sale find the probability that it will be July or October Answer the following problems using either addition rule make sure to reduce your fraction

Answer 1

Probability formula:

`\text{ P(E) = }\frac{\text{ N(Required outcome)}}{\text{N}(\text{Total outcome)}}\text{ }`

Total number of months in a year = 12

`\begin{gathered} \text{P(July) = }(1)/(12) \\ \text{P}(\text{October) =}(1)/(12) \end{gathered}`
`\begin{gathered} \text{ P(July or October) = P(July) + P(October)} \\ =(1)/(12)+(1)/(12)=(2)/(12) \end{gathered}`
`(2)/(12)=(1)/(6)`

Therefore, the probability that it will be July or October is 1/6