Question 1

The length of one side of the rectangles is twice the length of its adjacent side.If the perimeter of rectangle is `60cm` find the area of rectangle

Question 2

Given:

length=l ; breadth(b)=2l

$\begin{gathered} \text{Perimeter of a rectangle=2(l+b)} \\ 60=2(l+2l) \\ 60=2(3l) \\ 60=6l \\ l=10\operatorname{cm} \end{gathered}$
$\begin{gathered} \text{breadth(b)}=2l \\ \text{breadth(b)}=2(10) \\ \text{breadth(b)}=20\operatorname{cm} \end{gathered}$

length(l) = 10cm

breadth(b) = 20cm

$\begin{gathered} \text{Area of a rectangle=l}* b \\ \text{Area of a rectangle}=10*20 \\ \text{Area of a rectangle}=200cm^2 \end{gathered}$

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