First, let's simplify the expression to see the correct result:
![e^{(4)/(3)\ln 2-1}=\frac{e^{(4)/(3)\ln2}}{e}=\frac{e^{\ln 2^{(4)/(3)}}}{e}=\frac{2^{(4)/(3)}}{e}=\frac{\sqrt[3]{2^4}}{e}=\frac{\sqrt[3]{16}}{e}](https://img.qammunity.org/2023/formulas/mathematics/college/pgl4jurlr7bh733zy2wdbcfurpqz3xxvr1.png)
Looking at Helen's calculations, she did a mistake in the last step, where the numerator 4 went to the radical and denominator 3 went to the exponent of number 2, and it should be the inverse.
Looking at Stephen's calculations, he did a mistake in the first step, where he switched ln2 by 2, and that's not correct.