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What is the magnitude of the electrostatic force between two electrons separated by a distance of 2.00 × 10−8meter? The charge on an electron is −1.60 × 10−19C.1.15 × 10−20N7.20 × 10−2N5.76 × 10−13N3.60 × 106N

What is the magnitude of the electrostatic force between two electrons separated by-example-1
User Leeza
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1 Answer

5 votes

F = electrostatic forc

e = charge = -1.60 x 10^-19 C

k= Coulumb's constant = 9 x 10^9 Nm^2/C^2

r= distance = 2 x 10^-8 m

Apply:


F=k(e^2)/(r^2)

Replacing:

F= 9 x 10^9 ( -1.60x10^-19)^2 / (2x10^-8)^2

F= 5.76 x 10^-13 N

User Nathan Tregillus
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3.5k points