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To the nearest tenth, What is the area of a shaded segment when AG= 6 ft

To the nearest tenth, What is the area of a shaded segment when AG= 6 ft-example-1

1 Answer

3 votes

Answer:

28.3 square feet

Explanations:

The formula for calculating the area of the shaded segment is expressed as:


A=(1)/(2)* r^2(\theta-sin\theta)

where:

r is the radius = AG = 6ft

θ = 90 degrees

Substitute the given parameter into the formula


\begin{gathered} A=(1)/(2)*6^2((\pi)/(2)-sin((\pi)/(2))) \\ A=(1)/(2)*36((\pi)/(2)-1) \\ A=18((\pi)/(2)-1) \\ \end{gathered}

Since π = 3.14, then;


\begin{gathered} A=18((3.14)/(2)-1) \\ A=18(1.57-1) \\ A=18(0.57) \\ A=28.26 \\ A\approx28.3ft^2 \end{gathered}

Hence the area of the shaded region is 28.3 square feet

User Osm
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