Question

A chair lift is being built to the top of a mountain, 4,000vertical feet from the base. If the angle of inclination willbe a constant 30°, what length of cable is needed to reachfrom the top to the ground?

Answer 1

Step 1 :

In this question, we are meant to find the length of the cable needed to reach

from the top to the ground.

Step 2 :

From the question, we can see that :

`\begin{gathered} \sin 30^{0\text{ }}\text{ = }(4000)/(l) \\ \text{where l = length of the cable.} \\ 0.\text{ 5 = }(4000)/(l) \\ l\text{ =}\frac{4000}{0.\text{ 5}} \\ l\text{ = 8000 f}eet \end{gathered}`

CONCLUSION:

The length of the cable = 8000 feet.