It says that the given triangle is an isosceles triangle, which means that two of its sides are congruent.
As shown in the figure, the sides across ∠A and ∠C are congruent. This condition must also mean that ∠A and ∠C are congruent.
![\angle A\text{ = }\angle C](https://img.qammunity.org/2023/formulas/mathematics/college/xjxt9gxo50bvmp3x34gpc6a0vx10je3sjb.png)
∠C and its adjacent angle measuring 130° are Supplementary, which means that their sum is equal to 180°.
With this, we can get the measure of ∠C.
![\begin{gathered} \angle C+130^(\circ)=180^(\circ) \\ \angle C+130^(\circ)-130^(\circ)=180^(\circ)-130^(\circ) \\ \angle C=180^(\circ)-130^(\circ) \\ \angle C=50^(\circ) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ewbk1yp2q2laweh7cib65d73prh5q9a281.png)
But,
![\angle A\text{ = }\angle C](https://img.qammunity.org/2023/formulas/mathematics/college/xjxt9gxo50bvmp3x34gpc6a0vx10je3sjb.png)
Therefore, ∠A must also be equal to 50°.
![\angle A\text{ = }\angle C=50^(\circ)](https://img.qammunity.org/2023/formulas/mathematics/college/chi9fjbionsk6edn4rromia0lxed5gnusc.png)
The total sum of all interior angles of a triangle is 180°. With that relationship, we can determine the measure of ∠B since we've already determined the measure of ∠A and ∠C.
We get,
![\angle A\text{ + }\angle B\text{ + }\angle C=180^(\circ)](https://img.qammunity.org/2023/formulas/mathematics/college/jmt7rwnv8jyc4jm3iwy233hkk4v5818lg3.png)
![\begin{gathered} \text{ 50}^(\circ)\text{ + }\angle B+50^(\circ)=180^(\circ) \\ \angle B+100^(\circ)-100^(\circ)=180^(\circ)-100^(\circ) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/g52k14mpg1325ked1vj8r8n0aza5n5mkna.png)
![\angle B=80^(\circ)](https://img.qammunity.org/2023/formulas/mathematics/college/2xqdraf1173nnk73twzwdhkjer4xh8sm8d.png)
Therefore, ∠A = 50°, ∠B = 50° and ∠C = 80°.