Given:
Given that a right angle triangle.
![\begin{gathered} \theta=52.4\degree \\ h=16.7 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/zqmzhath5ootsea27u9yr7ed85kcgxhpbr.png)
Required:
To measure the each part of the triangle.
Step-by-step explanation:
Let the the two sides of triangle are a and o.
Now,
![\begin{gathered} \cos\theta=(a)/(h) \\ \\ \cos52.4=(a)/(16.7) \\ \\ 0.6101=(a)/(16.7) \\ \\ a=0.6101*16.7 \\ \\ a=10.188 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/482118upfpurc53pg6gf2jzo3rhi6no5wx.png)
Now we have to find the other side of the triangle.
Clearly the given triangle is right angle, therefore,
![\begin{gathered} h^2=a^2+o^2 \\ \\ 16.7^2=10.188^2+o^2 \\ \\ 278.98=103.795+o^2 \\ \\ o^2=175.184 \\ \\ o=13.23 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/bn3mrii8eymzbq1pkegqurn56wqn4a50sz.png)
Final Answer:
The other two sides of triangle are,
![\begin{gathered} 10.188 \\ 13.23 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/4og0va738dfqxbh530npvpt6cl2y9z8xbo.png)