item (a):
Using the formula given in the question, we have
![A=P(1+(r)/(n))^(nt)](https://img.qammunity.org/2023/formulas/mathematics/high-school/39foo2gerf9tf1ffk32zwshrn339mz02kv.png)
Our principal investment P is equal to $4000, our interest r is 3 1/4 %, writting this in decimal form we have
![3(1)/(4)=3+(1)/(4)=3.25](https://img.qammunity.org/2023/formulas/mathematics/high-school/5mpl741d96efc1cjiwp9qxtebu36ttdspv.png)
Since it is a percentage, to write in decimal we divide by 100
![(3.25)/(100)=0.0325](https://img.qammunity.org/2023/formulas/mathematics/high-school/46a26qj8fn8xq1s4y3mwysemlj7dug4dxk.png)
And finally, our n value is 365 since it is compounded daily, and we have 365 days in a year.
Then, our function is
![A(t)=4000(1+(0.0325)/(365))^(365t)_{}](https://img.qammunity.org/2023/formulas/mathematics/high-school/nuu5tcmy43jqbsuhs5mq7a720sx6wnldur.png)
item (b):
To find A(30), we just need to evaluate this value in the function we created before
![A(30)=4000(1+(0.0325)/(365))^(365\cdot30)_{}=10604.2085587\ldots\approx10604.21](https://img.qammunity.org/2023/formulas/mathematics/high-school/6jn36d83s71alyii2xbthfq5kuy8mjds53.png)
This means that with an investment of $4000, with this rate Joe is going to have a return of $10604.21.