Answer:
The probability that there is at least one infected person in group assigned for the task = 0.7
Step-by-step explanation:
Total number of crew members = 5
Number of infected persons = 2
Number of uninfected persons = 3
Probability that there is at least one infected person will be:
P(at least 1 infected) = P(1 infected) + P(2 infected)
Probability of selecting 1 infected person

![\begin{gathered} P(2\text{ }\imaginaryI\text{nfected persons}\operatorname{\rparen}=\frac{\text{2C2}}{\text{5C2}} \\ \\ P(2\text{ infected persons\rparen =}(1)/(10) \\ \\ P(2\text{ infected persons\rparen = 0.1} \end{gathered}]()
P(at least 1 infected) = P(1 infected) + P(2 infected)
P(at least 1 infected) = 0.6 + 0.1
P(at least 1 infected) = 0.7
The probability that there is at least one infected person in group assigned for the task = 0.7