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Rewrite the equation in center - radius form. Decide whether or not the equation has a circle as its graph. If it does not, describe the graph. x^2 + y^2 + 8x - 10y + 41 = 0

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The graph equation is given as;


x^{2\text{ }}+y^2+8x-10y+41=0

The format of the equation is ;


(x-h)^2+(y-k)^2=r^2

where ( h,k ) is the center and r is the radius


x^2-8x+y^2-10y=-41
x^2-8x+16+y^2-10y+25=\text{ -41 +16+25}
(x-4)^2+(y-5)^2=0

The equation has no circle as its graph because r=0

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