Question

Which two values of x are roots of the polynomial below?x2 + 3x + 5A. *= -3 + /292.O B. X=-3+/-112D.C. X=-3-v-11-3--11D. x= -3+, VTTE x=-3-DE. =-3-1129

Answer 1

Options B and C

Explanation:

Finding the roots of a quadratic equation:

Suppose that we have a quadratic equation in the following format:

ax² + bx + c = 0

The roots are given by:

`x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}`

In this question:

x² + 3x + 5 = 0

So a = 1, b = 3, c = 5

The roots are:

`x=\frac{-3\pm\sqrt[]{3^2-4\ast1\ast5}}{2}=\frac{-3\pm\sqrt[]{-11}}{2}`

So

`x=\frac{-3+\sqrt[]{-11}}{2},x=\frac{-3-\sqrt[]{-11}}{2}`

Options B and C