Question

Cynthia forgot to put the fabric softener in the wash. As her socks tumbled in the dryer, they became charged. If a small piece of lint with a charge of +1.25 E - 10 C is attracted to the socks by a force of 3.0 E - 6 N, what is the magnitude of the electric field at this location?

Answer 1

E = 24000 N/C = 24 KN/C

Step-by-step explanation:

The electric field experienced by a test charge is given by the following formula:

`E = (F)/(q)\\\\`

where,

E = Electric Field = ?

F = Force of attraction = 3 x 10⁻⁶ N

q = Charge on piece of lint = 1.25 x 10⁻¹⁰ C

Therefore, using these values in the equation, we get:

`E = (3\ x\ 10^(-6)\ N)/(1.25\ x\ ^(-10)\ C)\\\\`

E = 24000 N/C = 24 KN/C