Question

The area of a rectangular room is 750 square feet. The width of the room is 5 feet less than the length of the room.

Which equations can be used to solve for y, the length of the room? Select three options.

y(y + 5) = 750
y2 – 5y = 750
750 – y(y – 5) = 0
y(y – 5) + 750 = 0
(y + 25)(y – 30) = 0

Answer 1

B. y² – 5y = 750

C. 750 – y(y – 5) = 0

E. (y + 25)(y – 30) = 0

I'm assuming the 2 in the second option is supposed to be an exponent.

Explanation:

Length = y

Width = y-5

Length × Width = Area

Area = y(y-5) = 750

Distribute.

y²-5y=750 (B is correct)

If you factor the equation above

(y + 25)(y – 30) = 0 (E is correct)

Area = y(y-5) = 750

Subtract y(y-5) from both sides.

750-y(y-5) = 0 (C is correct)