Question

A concave lens has a focal length of 3.12 m. Solve for the magnification of the image on the film of a height 0.30 m, if the size of the image is 0.83 m

Answer 1

Given:

The focal length of the lens, f=3.12 m

The height of the film, h=0.30 m

The height of the image, h_i=0.83 m

To find:

The magnification of the lens.

Step-by-step explanation:

The magnification of a lens is given by,

`m=(h_i)/(h)`

On substituting the known values,

`\begin{gathered} m=(0.83)/(0.30) \\ =2.77\text{ } \end{gathered}`

Final answer:

The magnification of the lens is 2.77