Question

TTriangle H L I is shown. Line segment J K is drawn near point L to create triangle J L K. If △HLI ~ △JLK by the SSS similarity theorem, then StartFraction H L Over J L EndFraction = StartFraction I L Over K L EndFraction is also equal to which ratio? StartFraction H I Over J K EndFraction StartFraction H J Over J L EndFraction StartFraction I K Over K L EndFraction StartFraction J K Over H I EndFraction

Answer 1

its A

Explanation:

Answer 2

Question:

`\triangle`HLI is shown. Line segment JK is drawn near point L to create
`\triangle`JLK. If
`\triangle`HLI ~
`\triangle`JLK by the SSS similarity theorem, then
`(HL)/(JL) =(IL)/(KL)` is also equal to which ratio?

`(H I)/(J K)`
`(H J)/(J L)`
`(I K)/(K L)`
`(J K)/(H I)`

Answer:

`(H I)/(J K)`

Explanation:

Given

HLI ~
`\triangle`JLK

`(HL)/(JL) =(IL)/(KL)`

Required

Which other ratio equals
`(HL)/(JL) =(IL)/(KL)`

`\triangle`HLI ~
`\triangle`JLK implies that:

HL, IL and HI corresponds to JL, KL and JK respectively.

So, the possible ratios are:

HL : IL : HI = JL : KL : JK

Convert to fractions

`(HL)/(JL) = (IL)/(KL) = (HI)/(JK)`

So, from the list of options

`(H I)/(J K)` is equivalent to
`(HL)/(JL) =(IL)/(KL)`