Question

17 16 ✓ 15 ✓ 14 X 13 Ex la A training field is formed by joining a rectangle and two semicircles, as shown below. The rectangle is 96 m long and 58 m wide. m2 m Find the area of the training field. Use the value 3.14 for it, and do not round your answer. Be sure to include the correct unit in your answer. 96 m ? Х 58 m

Answer 1

The total area will be, the area of the two semi circles plus the area of the rectangle, so:

Area of the first semi circle:

`Ac1=(\pi r^2)/(2)=(\pi(29^2))/(2)=(841\pi)/(2)m^2`

Area of the rectangle:

`Ar=w\cdot l=96\cdot58=5568m^2`

Area of the second semi circle:

`Ac2=Ac1=(841\pi)/(2)m^2`

So, the total area is:

`A_T=(841\pi)/(2)m^2+5568m^2+(841\pi)/(2)=8208.74m^2`