Question

Need help solving this question (not from graded assignment just a review)

Answer 1

The expression given is,

`4x^5y^2\cdot \:2xy^(-3)`

Multiply the numbers:

`\begin{gathered} \:4\cdot \:2=8 \\ \therefore4x^5y^2*2xy^(-3)=8x^5y^2xy^{\left\{-3\right\}} \end{gathered}`

Simplify

`8x^5xy^2y^(-3)=8x^6y^2y^{\left\{-3\right\}}`

Also,

`\begin{gathered} y^2y^(-3)=y^(2-3)=y^(-1)=(1)/(y) \\ \therefore8x^6y^2y^{\left\{-3\right\}}=8x^6(1)/(y)=(8x^6)/(y) \end{gathered}`

Hence, the answer is

`(8x^(6))/(y)\text{ \lparen Option 2\rparen}`