1 Answer

Damarys · Answer 1 · 2023-09-23T12:16:14+0000

Given that the diameter of the wheel is d = 35 m.

Also, given that it completes 1 rev in 2 min 20 sec.

We have to find angular velocity, tangential velocity and centripetal acceleration.

The radius of the wheel will be

$\begin{gathered} r\text{ =}(d)/(2) \\ =(35)/(2) \\ =17.5\text{ m} \end{gathered}$

The tangential velocity is

$\begin{gathered} v=(2\pi r)/(t) \\ =(2*3.14*17.5)/(2*60+20) \\ =0.785\text{ m/s} \end{gathered}$

The angular velocity will be

$\begin{gathered} \omega=(v)/(r) \\ =(0.785)/(17.5) \\ =0.044\text{ rad/s} \end{gathered}$

The centripetal acceleration is

$\begin{gathered} a_c=(v^2)/(r) \\ =((0.785)^2)/(17.5) \\ =0.035m/s^2 \end{gathered}$

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