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1) The median is by nature more consistent and resistant to changes when some value is added to the data set. Let's visualize how that happens:
2) Mean
![\begin{gathered} \left\{13,6,13,8,2,19,11,16,17\right\} \\ \bar{x}=(13+6+13+8+2+19+11+16+17)/(9)=11.67 \\ 2)\operatorname{\{}13,\:6,\:13,\:8,\:2,\:19,\:11,\:16,\:17,32\operatorname{\}} \\ \bar{x}=(\sum_(i=1)^na_i=137)/(10)=13.7 \end{gathered}]()
As we can see, the addition of 32 to the data set changes the mean.
3) Now, let's check the Median. Rewriting that into the ascending order:

Note that 13 divides the distribution into two halves.
Now, let's add 32 to that dataset and check it:

Thus, we can tell that the answer is: