The given pyramid is compounded by four faces of triangles and one square. The area will be the sum of the individual area, as follows:
![\begin{gathered} A=A_(sq)+4A_(tr) \\ A=230\cdot230+4\cdot((187\cdot230)/(2)) \\ A=52,900+86,020 \\ \\ A=138,920\text{ m²} \end{gathered}]()
The surface area of the Great Pyramid, including the base, is:
138,920 m²
----------------------------------------------------------------------------------------------------------
The given Pyramid is made of four sides with the shape of a triangle and the basis with the shape of a square.
The area of the square is given by the product of the length of its side by itself. Because the length of the given square is 230 m, the area of the basi will be:
Now, the area of a single triangle is given by the product of its height by its base and divided by 2. Because the height of the given triangles are 187m and its base has a length of 230m, the area of a single triangle is given by:
Now, because there is four sides with a triangle shape and one base with a square shape, the total area will be the one calculated at the beginning of the present solution.
The surface area of the Great Pyramid, including the base, is:
138,920 m²