Question

Under certain conditions, the substance ammonium chloride can be broken down to form ammonia and hydrogen chloride.If 32.7 grams of ammonium chloride react to form 10.4 grams of ammonia, how many grams of hydrogen chloride must simultaneously be formed?

Answer 1

22.3g of hydrogen chloride are formed.

Step-by-step explanation:

1st) It is necessary to write and balance the chemical reaction:

`\begin{gathered} NH_4Cl\rightarrow NH_3+HCl \\ \end{gathered}`

From the balanced reaction we know that 1 mole of ammonium chloride (NH4) produces 1 mole of ammonia (NH3) and 1 mole of hydrogen chloride (HCl).

2nd) Using the molar mass of NH4Cl (53.5g/mol) and HCl (36.5g/mol), we can convert moles into grams.

Now we know that 53.5g of NH4Cl (1 mole) produces 36.5g of HCl (1 mole).

3rd) Finally, using the given value of ammonium chloride (32.7g) and with a mathematical rule of three we can calculate the grams of HCl that will be formed:

`\begin{gathered} 53.5gNH_4Cl-36.5gHCl \\ 32.7gNH_4Cl-x=(32.7gNH_4Cl*36.5gHCl)/(53.5gNH_4Cl) \\ x=22.3gHCl \end{gathered}`

So, 22.3g of hydrogen chloride are formed.