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Train A has a speed 15 miles per hour greater than that of train B. If train A travels 150 miles in the same timestrain B travels 105 miles, what are the speeds of the two trains?

User Alexloehr
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Take into account the following formula for the speed of an object:

v = d/t

where d is the distance travaled in time t. Solve the previous expression for t:

t = d/v

Consider that the speeds of both trains are v1 and v2 respectively. They traveled distance d1 = 150 mi and d2 = 105 mi in the same time t.

Then, you have:

t = 150/v1

t = 105/v2

furthermore, take into account that the speed of A is 15 mi/h greater than speed of train B, that is

v1 = v2 + 15

next, equal the expression for t and replace the previoues expression for v1, as follow:

150/(v2 + 15) = 105/(v2)

solve for v2:

150/(v2 + 15) = 105/(v2) multiply by v2(v2 +15) both sides

150·v2 = 105(v2 + 15) apply distributive property

150·v2 = 105·v2 + 1,575 subtract 105·v2 both sides and simplify

150·v2 - 105·v2 = 1,575

45·v2 = 1,575 divide by 45 both sides

v2 = 35

next, replace the previous value into the expression v1 = v2 + 15, to obtain v1:

v1 = 35 + 15 = 50

Hence, the spped of both trains A and B are 50 miles per hour and 35 miles per hour respectively

User Nooshin
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