Question

Solve for t in this quadratic equation0.15t2-44t+1200=0

Answer 1

Given the quadratic equation:

`0.15t^2-44t+1200=0`

Let's solve fot t.

Apply the standard quadratic equation:

`\begin{gathered} ax^2+bx+c=0 \\ \\ 0.15t^2-44t+1200=0 \end{gathered}`

Hence, we have the values:

• a = 0.15

,

• b = -44

,

• c = 1200

To solve for t apply the quadratic formula:

`t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}`

Thus, we have: