Question

Avogadro's law relates the volume of a gas to the number of moles of gaswhen temperature and pressure are constant. According to this law, howwould the volume of a gas change if a reaction produced 1 moles of gas from2 mole of gaseous reactants?

Answer 1

The volume will be one-half of the original volume

option A

Step-by-step explanation

Given that;

The initial moles of the gas is 2 moles

The final mole of the gas is 1 mole

The mathematical representation of the Avogadro's law is given below as

`\frac{\text{ V}_1}{\text{ n}_1}\text{ = }\frac{\text{ V}_2}{\text{ n}_2}`

Let n1 = 2 moles and n2 = 1 mole

`\begin{gathered} \text{ }\frac{\text{ V}_1}{\text{ 2}}\text{ = }\frac{\text{ V}_2}{\text{ 1}} \\ \text{ cross multiply} \\ \text{ V}_2\text{ }*\text{ 2 = V}_1\text{ }*\text{ 1} \\ \text{ Divide both sides by 2} \\ \text{ V}_2\text{ = }\frac{\text{ V}_{1\text{ }}}{\text{ 2}} \\ \frac{}{} \\ \text{ V}_2\text{ = }\frac{\text{ 1}}{\text{ 2}}V_1 \end{gathered}`

Therefore, the volume will be one-half of the original volume

option A