Question

Fred the frog is hopping from lily pad to lily pad in search of a good fly forlunch. If the lily pads are spaced 2,4 m apart, and Fred jumps with a speedof 5.0 m/s, taking 0.60 s to go from lily pad to lily pad, at what angle mustFred make each of his jumps? (Use 10 for g)

Answer 1

36.87°

Step-by-step explanation:

The frog is making a projectile motion, so the time of flight for each jump is calculated as

`t=(2v_0\sin\theta)/(g)`

Where vo is the initial velocity, g is the gravity and θ is the angle. Solving for sinθ, we get

`\begin{gathered} tg=2v_0\sin\theta \\ \sin\theta=(tg)/(2v_0) \end{gathered}`

Replacing t = 0.60 s, v0 = 5.0 m/s, and g = 10 m/s², we get

`\begin{gathered} \sin\theta=\frac{(0.60\text{ s\rparen}(10\text{ m/s}^2\text{\rparen}}{2(5.0\text{ m/s\rparen }} \\ \sin\theta=0.6 \\ \theta=\sin^(-1)(0.6) \\ \theta=36.87 \end{gathered}`

Therefore, the angle is 36.87°