Question

What is the molarity of a solution that contain 90 g of sodium chloride in 3.5 L solution

Answer 1

`0.44\text{ M}`

Step-by-step explanation:

Here, we want to get the molarity of the solution

Mathematically, we have that calculated as:

`\begin{gathered} molarity\text{ = }\frac{number\text{ of moles}}{volume} \\ \\ number\text{ of moles = }\frac{mass}{molar\text{ mass}} \end{gathered}`

We start by getting the number of moles

We can get that by dividing the mass by the molar mass

The molar mass of NaCl is 58.44 g/mol

The number of moles is thus:

`number\text{ of moles = }(90)/(58.44)\text{ = 1.54 mole}`

To get the molarity, we have it that:

`molarity\text{ = }(1.54)/(3.5)\text{ = 0.44 M}`