Question

What is the molarity of a solution that has 78 grams of H2SO4, (98.0 g/mol) dissolved in 1.75 liters ofsolution?

Answer 1

Molarity (C) = 0.455 mol/L

Step-by-step explanation

Given:

Mass of H2SO4 = 78 g

Molar mass of H2SO4 = 98.0 g/mol

Volume of the solution = 1.75 L

Required: The molarity of the solution

Solution

Step 1: Calculate the number of moles of moles of H2SO4

n = m/M where n is the moles, m is the mass and M is the molar mass

n = 78 g/98.0 g/mol

n = 0.796 mol

Step 2: Calculate the molarity of the solution

C = n/V where C is the molarity/concentration, and V is the volume of the solution

C = 0.796 mol/1.75 L

C = 0.455 mol/L