Question

What is the intensity of a sound wave if the power output of the source is 3.56 W and the surface area is 1.58 m²?0.444 W/m²5.62 W/m²2.25 W/m²1.98 W/m²

Answer 1

Given:

The power output of the source is

`P=3.56\text{ W}`

The surface area is,

`A=\text{ 1.58 m}^2`

Required: intensity of the sound wave

Step-by-step explanation:

The intensity of the sound wave can be found by the formula.

that is given by,

`I=(P)/(A)`

here, P is the power output of the source and A is the surface area.

Plugging all the values in the above formula, we get:

`\begin{gathered} I=\frac{3.56\text{ W}}{1.58\text{ m}^2} \\ I=2.25\text{ w/m}^2 \end{gathered}`

Result: Thus, the intensity of the sound wave is

`2.25\text{ w/m}^2`

and the option 3rd is correct.