Given the system of equations:
• 6x - 2y = 36
,
• -3x + 3y = 12
The solution:
(x, y) ==> (11, 15)
Let's determine whether the given ordered pair is a solution to the system of equations.
Let's solve the system using the addition and elimination method.
Multiply both equations so the coefficients of one variable are opposite.
Multiply equation 2 by 2:
6x - 2y = 36
2(-3x + 3y) = 2(12)
• 6x - 2y = 36
,
• -6x + 6y = 24
Add both equations:
6x - 2y = 36
-6x + 6y = 24
____________
0 + 4y = 60
We now have:
4y = 60
Divide both sides by 4:
![\begin{gathered} (4y)/(4)=(60)/(4) \\ \\ y=15 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/zxyjri1kh7zhgsa1w630ocj5u4a27xaufj.png)
Plug in 15 for y in either of the equations.
Take the first equation:
![\begin{gathered} 6x-2y=36 \\ \\ 6x-2(15)=36 \\ \\ 6x-30=36 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/z1n2g7vidxhuz6atjpjsbthp3l39bqxng0.png)
Add 30 to both sides:
![\begin{gathered} 6x-30+30=36+30 \\ \\ 6x=66 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/itsmjvlpmlfkykf1dxk8b9jr9fakodzk4f.png)
Divide both sides by 6:
![\begin{gathered} (6x)/(6)=(66)/(6) \\ \\ x=11 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/9xydvxtfv0f4eg6ddou8phim1i3frs2ubf.png)
Therefore, the solution is:
x = 11, y = 15
In point form, the solution is: (11, 15)
Therefore, the given ordered pair is a solution to the system of equations.
ANSWER:
Yes, the ordered pair is a solution to the system of equations.