The molar volume of an ideal gas at STP is
22.4
d
m
3
, or
22.4
L
.
Step-by-step explanation:
In one mole of gas there are Avogadro's number of particles. There are
6.022
×
10
23
particles mol
−
1
.
So how many moles are there in
4.02
×
10
22
helium particles?
It is simply the quotient:
4.02
×
10
22
helium particles
6.022
×
10
23
helium particles mol
−
1
=
?
?
m
o
l
The volume of course is the prior quotient mulitplied by the molar volume of an ideal gas:
4.02
×
10
22
helium particles
6.022
×
10
23
helium particles mol
−
1
×
22.4
⋅
L
⋅
m
o
l
−
1