Question

A metal sphere with a charge of +25 x 10-9 C is placed 2 m away from another metal sphere which carries a charge of +10 x 10^-9 C. What is the magnitude and direction of the electric force between the two metal spheres?

Answer 1

F = 5.625 10⁻⁷ N

Step-by-step explanation:

For this exercise we use coulomb's law

F =
`k \ (q_1q_2)/(r^2)`

where k is the Coulomb constant which is equal to 9 10⁺⁹ N m² /C²

as the charge on the two spheres has the same sign, the force is repulsive,

let's calculate

F = 9 10⁹ 25 10⁻⁹ 10 10⁻⁹ / 2²

F = 5.625 10⁻⁷ N