The equation of a line is:
![y-y_1=m(x-x_1)](https://img.qammunity.org/2023/formulas/mathematics/high-school/csobd57zth7rh9k4hz9amldzpq2owf0z4j.png)
where (x1,y1) is a point in the line and m is the slope.
In our case we have two points but we don't have the slope yet, to find it we need to remember that the slope is given by:
![m=(y_2-y_1)/(x_2-x_1)](https://img.qammunity.org/2023/formulas/mathematics/high-school/78uaqhwt0aws3qfwxigaftpihnmb1gzxtp.png)
Then, in our case:
![\begin{gathered} m=(1-(-2))/(4-2) \\ =(1+2)/(2) \\ =(3)/(2) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/9ulq4hoal2uo5j1vt01habfipb6m200wix.png)
Then, the equation of the line is:
![\begin{gathered} y-1=(3)/(2)(x-4) \\ 2y-2=3x-12 \\ 3x-2y=-2+10 \\ 3x-2y=10 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/8p2b96ybrs06up9pfo7i8zp2a6mpvdgk8g.png)
Therefore the answer is A.