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Find the slope of a line parallel to -5y + 2 = 3x ?a. -3/5b. -5/3C. 3/5d. 5/3

User Askvictor
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1 Answer

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Subtracting 2 from the given equation we get:


\begin{gathered} -5y+2-2=3x-2, \\ -5y=3x-2. \end{gathered}

Dividing by -5 we get:


\begin{gathered} (-5y)/(-5)=(3x)/(-5)-(2)/(-5), \\ y=-(3)/(5)x+(2)/(5)\text{.} \end{gathered}

The above equation is in slope-intercept form, therefore, the slope of the given line is:


-(3)/(5)\text{.}

Now, recall that two lines are parallel if they have the same slope.

Answer: Option a.

User M R
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