Question

A parabola opening up or down has vertex (0, 1) and passes through (8, -3). Write its equation invertex form.

Answer 1

Step-by-step explanation

The parabola in vertex form is given as

`y=a(x-h)^2+k`

Where (h,k) is the vertex.

`y=a(x-0)^2+1`

Therefore, since the parabola passes through (8,-3)

We will have;

`\begin{gathered} -3=a(8)^2+1 \\ -3=64a+1 \\ 64a=-4 \\ a=-(4)/(64) \\ a=-(1)/(16) \end{gathered}`

Therefore;

Answer:

`y=-(1)/(16)(x-0)^2+1`