Question

A block with a mass of 22.3 kg is pulled by a rope with a force of 5.94 N. What acceleration (in m/s2) does the block experience?

Answer 1

Given that the mass of the block is m = 22.3 kg

The force applied is F = 5.94 N

We have to find the acceleration of the block.

The acceleration of the block is given by the formula

`a=(F)/(m)`

Substituting the values, the acceleration will be

`\begin{gathered} a=\text{ }(5.94)/(22.3) \\ =0.267m/s^2 \end{gathered}`

Thus, the acceleration is 0.267 m/s^2