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Six angles of a convex octagon is congruent. Each of the two remaining angles is 20 degrees more than one of the other six angles. Find the measure of EACH angle.

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Determine the sum of angles of octagon.


\begin{gathered} S=(n-2)*180 \\ =(8-2)*180 \\ =6\cdot180 \\ =1080 \end{gathered}

Let measure of each angle of six congurent angle be x.

Then measure of each of other two remaining angle is (x + 20).

Determine the value of x by using the sum of angles of octagon.


\begin{gathered} x+x+x+x+x+x+x+20+x+20=1080 \\ 8x=1080-40 \\ x=(1040)/(8) \\ =130 \end{gathered}

So measure of each angle of six congurent angle is 130 degree.

Determine the measure of two remaining angles.


\begin{gathered} x+20=130+20 \\ =150 \end{gathered}

Thus measure of angles of octagone are,

Six angle measure 130 degree each and two angle measure 150 degree each.


130,130,130,130,130,130,150,150

User LarsC
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