Given:
The gravitational force between two objects is,
![16\text{ units}](https://img.qammunity.org/2023/formulas/physics/college/1jo08oz28d52lepayo6jqgfm5za9pb00dh.png)
The mass of object 1 was doubled.
The distance between the objects was tripled.
To find:
The new force of attraction between the two objects
Step-by-step explanation:
The force of attraction between two objects at a distance 'r' is,
![F=(Gm_1m_2)/(r^2)](https://img.qammunity.org/2023/formulas/physics/college/o17slql8zhfxufgswvdbl9021lqzu8lnir.png)
According to the question,
![(Gm_1m_2)/(r^2)=16](https://img.qammunity.org/2023/formulas/physics/college/g73fag9xoass78qje3q7cwzewkod3mek6o.png)
The new force of attraction is,
![\begin{gathered} F^(\prime)=(G*2m_1* m_2)/((3r)^2) \\ =(2Gm_1m_2)/(9r^2) \\ =(2)/(9)F \\ =(2)/(9)*16\text{ units} \\ =(32)/(9)\text{ units} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/j0qtdzdskfqn9oobob6lleen9u0wyv8t3r.png)
Hence, the new force of attraction is 32/9 units.