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Suppose that two objects attract each other with a gravitational force of 16 units. If the mass of object 1 was doubled, and if the distance between the objects was tripled, then what would be the new force of attraction between the two objects?

Suppose that two objects attract each other with a gravitational force of 16 units-example-1
User Dritan
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1 Answer

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Given:

The gravitational force between two objects is,


16\text{ units}

The mass of object 1 was doubled.

The distance between the objects was tripled.

To find:

The new force of attraction between the two objects

Step-by-step explanation:

The force of attraction between two objects at a distance 'r' is,


F=(Gm_1m_2)/(r^2)

According to the question,


(Gm_1m_2)/(r^2)=16

The new force of attraction is,


\begin{gathered} F^(\prime)=(G*2m_1* m_2)/((3r)^2) \\ =(2Gm_1m_2)/(9r^2) \\ =(2)/(9)F \\ =(2)/(9)*16\text{ units} \\ =(32)/(9)\text{ units} \end{gathered}

Hence, the new force of attraction is 32/9 units.

User Skkakkar
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