Question

A 3.5 kg artillery shell is shot out of a cannon at 375 m/s. If it plunges 1.3 minto an enemy bunker, what is the average force that the shell exerts on thebunker wall?

Answer 1

Given

A m=3.5 kg artillery shell is shot out of a cannon at v=375 m/s. It plunges into enemy bunker to s=1.3 m.

To find

The force

Step-by-step explanation

Let the force be F.

By work-energy theorem,

Work done is equivalent to the energy.

Thus,

`\begin{gathered} (1)/(2)mv^2=F* s \\ \Rightarrow(1)/(2)3.5*375^2=1.3F \\ \Rightarrow F=1.8*10^5N \end{gathered}`

Conclusion

The force that the shell exerts is

`1.8*10^5N`