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Need help with this one 3 tutors have canceled I been on it for 30 min

Need help with this one 3 tutors have canceled I been on it for 30 min-example-1
User Neouyghur
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Answer: We have to find the JK, the simple answer is as follows, it is calculated by first finding the angle M and then using a trigonometric ratio to calculate the JK.

The simple and brief steps are as follows:


\begin{gathered} \angle M=\theta_T=\sin^(-1)((LJ)/(LM))=\sin^(-1)((12)/(20))=36.869897646^(\circ) \\ \\ \theta=(\theta_T)/(2)=18.434948823^(\circ)\approx18.435^(\circ) \end{gathered}

Therefore the JK is:


\begin{gathered} \tan(\theta)=(JK)/(JM)\rightarrow\tan(18.435^(\circ))=(JK)/(16) \\ \\ \\ JK=16\tan(18.435^(\circ))=5.3333333\approx5.34 \\ \\ \\ JK\approx5.34 \end{gathered}

Therefore JK is 5.34.

User Graham Lee
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